%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEV409^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n189.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:34:09 EDT 2014

% Result   : Unknown 2.84s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEV409^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n189.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 09:09:46 CDT 2014
% % CPUTime  : 2.84 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula ((ex ((fofType->Prop)->((fofType->Prop)->Prop))) (fun (R:((fofType->Prop)->((fofType->Prop)->Prop)))=> (forall (X:(fofType->Prop)) (Y:(fofType->Prop)), (((and ((R X) Y)) ((R Y) X))->(forall (Xx:fofType), ((iff (X Xx)) (Y Xx))))))) of role conjecture named cTHM120_BUG_pme
% Conjecture to prove = ((ex ((fofType->Prop)->((fofType->Prop)->Prop))) (fun (R:((fofType->Prop)->((fofType->Prop)->Prop)))=> (forall (X:(fofType->Prop)) (Y:(fofType->Prop)), (((and ((R X) Y)) ((R Y) X))->(forall (Xx:fofType), ((iff (X Xx)) (Y Xx))))))):Prop
% Parameter fofType_DUMMY:fofType.
% We need to prove ['((ex ((fofType->Prop)->((fofType->Prop)->Prop))) (fun (R:((fofType->Prop)->((fofType->Prop)->Prop)))=> (forall (X:(fofType->Prop)) (Y:(fofType->Prop)), (((and ((R X) Y)) ((R Y) X))->(forall (Xx:fofType), ((iff (X Xx)) (Y Xx)))))))']
% Parameter fofType:Type.
% Trying to prove ((ex ((fofType->Prop)->((fofType->Prop)->Prop))) (fun (R:((fofType->Prop)->((fofType->Prop)->Prop)))=> (forall (X:(fofType->Prop)) (Y:(fofType->Prop)), (((and ((R X) Y)) ((R Y) X))->(forall (Xx:fofType), ((iff (X Xx)) (Y Xx)))))))
% % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
%------------------------------------------------------------------------------